The Handshake Puzzle: A Unique Scenario Explained
Imagine a scenario in which ten people are in a house, and each individual wants to shake hands with only those individuals who are shorter than themselves. How many handshakes would occur in this unique height-based interaction?
Understanding the Handshake Puzzle
In this scenario, the handshaking rule is that each person only shakes hands with those who are shorter than themselves. This leads to an interesting analysis of the situation:
Everyone Is of Different Heights
Given that everyone has a unique height, the tallest person will not shake hands with anyone, as there is no one taller. Conversely, the shortest person will not shake hands with anyone either, as there is no one shorter. For any person in between, the rule dictates that they will shake hands with all the individuals who are shorter.
Breaking Down the Handshakes
Let's count the handshakes:
The tallest person will not shake hands with anyone (0 handshakes). The second tallest will shake hands with 1 person (the shortest). The third tallest will shake hands with 2 people (the two shortest). The fourth tallest will shake hands with 3 people. This pattern continues down to the shortest person, who shakes hands with no one.So, we need to sum the handshakes:
0 1 2 3 4 5 6 7 8 9The total number of handshakes is given by the formula for the sum of the first n natural numbers: (frac{n(n 1)}{2}).
Total Handshakes Calculation
Substituting (n 9) into the formula:
[ text{Total Handshakes} frac{9(9 1)}{2} frac{9 times 10}{2} 45 ]Hence, the total number of handshakes made is 45.
Alternative Interpretation
One might argue that the tallest person wants to shake hands with 9 people, the second tallest with 8, and so on. This perspective also leads to the same conclusion, as it essentially forms 5 matched pairs (9, 8, 7, 6, 5) each totaling 9, summing up to 45.
However, the method of counting by the mathematical sum of the first n natural numbers provides a clear and concise way to arrive at the solution.
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